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!1330 增加分段锁实现 (issue#IBYLR1@Gitee)
Merge pull request !1330 from 大阔/v5-dev
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package cn.hutool.core.thread;
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import cn.hutool.core.collection.CollUtil;
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import cn.hutool.core.thread.lock.SegmentLock;
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import org.junit.jupiter.api.BeforeEach;
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import org.junit.jupiter.api.Test;
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import java.util.ArrayList;
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import java.util.List;
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import java.util.concurrent.*;
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import java.util.concurrent.atomic.AtomicBoolean;
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import java.util.concurrent.locks.Lock;
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import java.util.concurrent.locks.ReadWriteLock;
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import static org.junit.jupiter.api.Assertions.*;
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/**
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* SegmentLock 单元测试类
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*/
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public class SegmentLockTest {
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private static final int SEGMENT_COUNT = 4;
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private SegmentLock<Lock> strongLock;
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private SegmentLock<Lock> weakLock;
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private SegmentLock<Semaphore> semaphore;
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private SegmentLock<ReadWriteLock> readWriteLock;
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@BeforeEach
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public void setUp() {
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strongLock = SegmentLock.lock(SEGMENT_COUNT);
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weakLock = SegmentLock.lazyWeakLock(SEGMENT_COUNT);
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semaphore = SegmentLock.semaphore(SEGMENT_COUNT, 2);
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readWriteLock = SegmentLock.readWriteLock(SEGMENT_COUNT);
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}
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@Test
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public void testSize() {
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assertEquals(SEGMENT_COUNT, strongLock.size());
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assertEquals(SEGMENT_COUNT, weakLock.size());
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assertEquals(SEGMENT_COUNT, semaphore.size());
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assertEquals(SEGMENT_COUNT, readWriteLock.size());
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}
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@Test
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public void testGetWithSameKey() {
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// 相同 key 应返回相同锁
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String key1 = "testKey";
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String key2 = new String("testKey"); // equals 但不同对象
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Lock lock1 = strongLock.get(key1);
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Lock lock2 = strongLock.get(key2);
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assertSame(lock1, lock2, "相同 key 应返回同一锁对象");
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Lock weakLock1 = weakLock.get(key1);
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Lock weakLock2 = weakLock.get(key2);
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assertSame(weakLock1, weakLock2, "弱引用锁相同 key 应返回同一锁对象");
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}
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@Test
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public void testGetAt() {
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for (int i = 0; i < SEGMENT_COUNT; i++) {
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Lock lock = strongLock.getAt(i);
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assertNotNull(lock, "getAt 返回的锁不应为 null");
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}
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assertThrows(IllegalArgumentException.class, () -> strongLock.getAt(SEGMENT_COUNT),
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"超出段数的索引应抛出异常");
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}
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@Test
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public void testBulkGet() {
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List<String> keys = CollUtil.newArrayList("key1", "key2", "key3");
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Iterable<Lock> locks = strongLock.bulkGet(keys);
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List<Lock> lockList = CollUtil.newArrayList(locks);
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assertEquals(3, lockList.size(), "bulkGet 返回的锁数量应与 key 数量一致");
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// 检查顺序性
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int prevIndex = -1;
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for (Lock lock : lockList) {
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int index = findIndex(strongLock, lock);
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assertTrue(index >= prevIndex, "bulkGet 返回的锁应按索引升序");
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prevIndex = index;
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}
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}
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@Test
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public void testLockConcurrency() throws InterruptedException {
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int threadCount = SEGMENT_COUNT * 2;
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CountDownLatch startLatch = new CountDownLatch(1);
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CountDownLatch endLatch = new CountDownLatch(threadCount);
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ExecutorService executor = Executors.newFixedThreadPool(threadCount);
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List<String> keys = new ArrayList<>();
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for (int i = 0; i < threadCount; i++) {
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keys.add("key" + i);
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}
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for (int i = 0; i < threadCount; i++) {
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final String key = keys.get(i);
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executor.submit(() -> {
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try {
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startLatch.await();
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Lock lock = strongLock.get(key);
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lock.lock();
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try {
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Thread.sleep(100); // 模拟工作
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} finally {
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lock.unlock();
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}
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} catch (InterruptedException e) {
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Thread.currentThread().interrupt();
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} finally {
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endLatch.countDown();
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}
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});
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}
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startLatch.countDown();
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assertTrue(endLatch.await(2000, java.util.concurrent.TimeUnit.MILLISECONDS),
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"并发锁测试应在 2 秒内完成");
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executor.shutdown();
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}
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@Test
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public void testSemaphore() {
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Semaphore sem = semaphore.get("testKey");
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assertEquals(2, sem.availablePermits(), "信号量初始许可应为 2");
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sem.acquireUninterruptibly(2);
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assertEquals(0, sem.availablePermits(), "获取所有许可后应为 0");
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sem.release(1);
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assertEquals(1, sem.availablePermits(), "释放一个许可后应为 1");
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}
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@Test
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public void testReadWriteLock() throws InterruptedException {
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ReadWriteLock rwLock = readWriteLock.get("testKey");
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Lock readLock = rwLock.readLock();
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Lock writeLock = rwLock.writeLock();
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// 测试读锁可重入
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readLock.lock();
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assertTrue(readLock.tryLock(), "读锁应允许多个线程同时持有");
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readLock.unlock();
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readLock.unlock();
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CountDownLatch latch = new CountDownLatch(1);
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ExecutorService executor = Executors.newSingleThreadExecutor();
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AtomicBoolean readLockAcquired = new AtomicBoolean(false);
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writeLock.lock();
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executor.submit(() -> {
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readLockAcquired.set(readLock.tryLock());
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latch.countDown();
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});
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latch.await(500, TimeUnit.MILLISECONDS);
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assertFalse(readLockAcquired.get(), "写锁持有时读锁应失败");
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writeLock.unlock();
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executor.shutdown();
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executor.awaitTermination(1, TimeUnit.SECONDS);
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}
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@Test
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public void testWeakReferenceCleanup() throws InterruptedException {
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SegmentLock<Lock> weakLockLarge = SegmentLock.lazyWeakLock(1024); // 超过 LARGE_LAZY_CUTOFF
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Lock lock = weakLockLarge.get("testKey");
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System.gc();
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Thread.sleep(100);
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// 弱引用锁未被其他引用,应仍可获取
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Lock lockAgain = weakLockLarge.get("testKey");
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assertSame(lock, lockAgain, "弱引用锁未被回收时应返回同一对象");
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}
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@Test
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public void testInvalidSegmentCount() {
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assertThrows(IllegalArgumentException.class, () -> SegmentLock.lock(0),
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"段数为 0 应抛出异常");
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assertThrows(IllegalArgumentException.class, () -> SegmentLock.lock(-1),
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"负段数应抛出异常");
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}
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@Test
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public void testHashDistribution() {
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SegmentLock<Lock> lock = SegmentLock.lock(4);
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int[] counts = new int[4];
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for (int i = 0; i < 100; i++) {
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int index = findIndex(lock, lock.get("key" + i));
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counts[index]++;
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}
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for (int count : counts) {
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assertTrue(count > 0, "每个段都应至少被分配到一个 key");
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}
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}
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private int findIndex(SegmentLock<Lock> lock, Lock target) {
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for (int i = 0; i < lock.size(); i++) {
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if (lock.getAt(i) == target) {
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return i;
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}
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}
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return -1;
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}
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}
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